C语言程序设计第四版（何钦铭、颜晖）第八章之利用指针返回多个结果
【练习8-3】计算两个数的和与差。要求自定义函数sum_diff(double op1,double op2,double *psum,double *pdiff),实现计算两个数的和与差,其中op1和op2是需要计算的两个数,psum和pdiff指向的变量保存计算得出的和与差。#includestdio.h double caculate(double op1,double op2,double *psum,double *pdiff); int main() { double op1,op2,sum,diff; scanf(%lf%lf,op1,op2); caculate(op1,op2,sum,diff); printf(%.3f%.3f%.3f,%.3f-%.3f%.3f,op1,op2,sum,op1,op2,diff); return 0; } double caculate(double op1,double op2,double *psum,double *pdiff){ *psumop1op2; *pdiffop1-op2; }输入样例23 8输出结果23.0008.00031.000,23.000-8.00015.000
