编写python程序算出1-13的全部4个数字组合允许重复加减乘除能够算出24点的组合及对应的表达式比如1234:1x2x3x4,用A、B、C、D表示10、11、12、13用圆括号表示运算优先级。用最简的高效语句完成无需注释。不做别的fromitertoolsimportproduct,permutations,combinations_with_replacementfromfractionsimportFractiondefsolve_24():ops[,-,*,/]numberslist(range(1,14))results[]card_map{10:A,11:B,12:C,13:D}fornumsincombinations_with_replacement(numbers,4):foundset()fora,b,c,dinset(permutations(nums)):forop1,op2,op3inproduct(ops,repeat3):expressions[f(({a}{op1}{b}){op2}{c}){op3}{d},f({a}{op1}({b}{op2}{c})){op3}{d},f({a}{op1}{b}){op2}({c}{op3}{d}),f{a}{op1}(({b}{op2}{c}){op3}{d}),f{a}{op1}({b}{op2}({c}{op3}{d}))]forexprinexpressions:try:ifabs(eval(expr)-24)1e-6:dispexprfork,vincard_map.items():dispdisp.replace(str(k),v)found.add(disp)breakexceptZeroDivisionError:continueiffound:breakiffound:breakiffound:num_str.join(card_map.get(x,str(x))forxinnums)results.append(f{num_str}:{,.join(found)})returnresultsforlineinsolve_24():print(line)第一版用eval函数实现效率比较低继续提示要求不用eval函数实现其他要求同上。fromitertoolsimportproduct,permutations,combinations_with_replacementdefsolve_24():ops{:lambdax,y:xy,-:lambdax,y:x-y,*:lambdax,y:x*y,/:lambdax,y:x/yify!0elseNone}numberslist(range(1,14))results[]card_map{10:A,11:B,12:C,13:D}fornumsincombinations_with_replacement(numbers,4):foundset()fora,b,c,dinset(permutations(nums)):forop1,op2,op3inproduct(ops.keys(),repeat3):f1,f2,f3ops[op1],ops[op2],ops[op3]try:ifabs(f3(f2(f1(a,b),c),d)-24)1e-6:exprf(({a}{op1}{b}){op2}{c}){op3}{d}fork,vincard_map.items():exprexpr.replace(str(k),v)found.add(expr)elifabs(f3(f1(a,f2(b,c)),d)-24)1e-6:exprf({a}{op1}({b}{op2}{c})){op3}{d}fork,vincard_map.items():exprexpr.replace(str(k),v)found.add(expr)elifabs(f2(f1(a,b),f3(c,d))-24)1e-6:exprf({a}{op1}{b}){op2}({c}{op3}{d})fork,vincard_map.items():exprexpr.replace(str(k),v)found.add(expr)elifabs(f2(a,f3(f1(b,c),d))-24)1e-6:exprf{a}{op1}(({b}{op2}{c}){op3}{d})fork,vincard_map.items():exprexpr.replace(str(k),v)found.add(expr)elifabs(f1(a,f2(b,f3(c,d)))-24)1e-6:exprf{a}{op1}({b}{op2}({c}{op3}{d}))fork,vincard_map.items():exprexpr.replace(str(k),v)found.add(expr)except(TypeError,ZeroDivisionError):continueiffound:breakiffound:breakiffound:num_str.join(card_map.get(x,str(x))forxinnums)results.append(f{num_str}:{,.join(found)})returnresultsforlineinsolve_24():print(line)再测试Qwen编写python程序算出1-13的全部4个数字组合允许重复加减乘除能够算出24点的组合及对应的表达式每行只要输出1个解比如1234:1x2x3x4用A、B、C、D表示10、11、12、13用圆括号表示运算优先级。要求不用eval函数实现, 用最简的高效语句完成无需注释。不做别的第一版程序报错执行报错 File C:\d\qw24.py, line 26, in solve r5 calc(calc(a, calc(b, c, o1), o2), d, o3) File C:\d\qw24.py, line 5, in calc if op : return a b ~~^~~ TypeError: unsupported operand type(s) for : NoneType and int请改正不做别的。其他要求不变fromitertoolsimportproduct,permutations ops[,-,*,/]numslist(range(1,14))defcalc(a,b,op):ifaisNoneorbisNone:returnNoneifop:returnabifop-:returna-bifop*:returna*bifop/:returna/bifb!0elseNonedeffmt(n):returnstr(n)ifn10elseABCD[n-10]defsolve():forcomboinproduct(nums,repeat4):forpinset(permutations(combo)):a,b,c,dpforo1inops:foro2inops:foro3inops:r1calc(calc(calc(a,b,o1),c,o2),d,o3)ifr124:print(f{fmt(a)}{fmt(b)}{fmt(c)}{fmt(d)}:(({fmt(a)}{o1}{fmt(b)}){o2}{fmt(c)}){o3}{fmt(d)});continuer2calc(calc(a,b,o1),calc(c,d,o2),o3)ifr224:print(f{fmt(a)}{fmt(b)}{fmt(c)}{fmt(d)}:({fmt(a)}{o1}{fmt(b)}){o3}({fmt(c)}{o2}{fmt(d)}));continuer3calc(a,calc(b,calc(c,d,o2),o1),o3)ifr324:print(f{fmt(a)}{fmt(b)}{fmt(c)}{fmt(d)}:{fmt(a)}{o3}({fmt(b)}{o1}({fmt(c)}{o2}{fmt(d)})));continuer4calc(a,calc(calc(b,c,o1),d,o2),o3)ifr424:print(f{fmt(a)}{fmt(b)}{fmt(c)}{fmt(d)}:{fmt(a)}{o3}(({fmt(b)}{o1}{fmt(c)}){o2}{fmt(d)}));continuer5calc(calc(a,calc(b,c,o1),o2),d,o3)ifr524:print(f{fmt(a)}{fmt(b)}{fmt(c)}{fmt(d)}:({fmt(a)}{o2}({fmt(b)}{o1}{fmt(c)})){o3}{fmt(d)});continuesolve()第二版算出了所有解继续提示每个4数字组合只要输出一个解每个组合都按数字大小排序比如13CD注意将if r1 24改为if abs(r1 -24)1e-6等不做别的其他要求不变最终程序如下fromitertoolsimportcombinations_with_replacement,permutations ops[,-,*,/]numslist(range(1,14))defcalc(a,b,op):ifaisNoneorbisNone:returnNoneifop:returnabifop-:returna-bifop*:returna*bifop/:returna/bifb!0elseNonedeffmt(n):returnstr(n)ifn10elseABCD[n-10]defsolve():forcomboincombinations_with_replacement(nums,4):foundFalseforpinset(permutations(combo)):iffound:breaka,b,c,dpforo1inops:iffound:breakforo2inops:iffound:breakforo3inops:r1calc(calc(calc(a,b,o1),c,o2),d,o3)ifr1isnotNoneandabs(r1-24)1e-6:print(f{fmt(combo[0])}{fmt(combo[1])}{fmt(combo[2])}{fmt(combo[3])}:(({fmt(a)}{o1}{fmt(b)}){o2}{fmt(c)}){o3}{fmt(d)})foundTrue;breakr2calc(calc(a,b,o1),calc(c,d,o2),o3)ifr2isnotNoneandabs(r2-24)1e-6:print(f{fmt(combo[0])}{fmt(combo[1])}{fmt(combo[2])}{fmt(combo[3])}:({fmt(a)}{o1}{fmt(b)}){o3}({fmt(c)}{o2}{fmt(d)}))foundTrue;breakr3calc(a,calc(b,calc(c,d,o2),o1),o3)ifr3isnotNoneandabs(r3-24)1e-6:print(f{fmt(combo[0])}{fmt(combo[1])}{fmt(combo[2])}{fmt(combo[3])}:{fmt(a)}{o3}({fmt(b)}{o1}({fmt(c)}{o2}{fmt(d)})))foundTrue;breakr4calc(a,calc(calc(b,c,o1),d,o2),o3)ifr4isnotNoneandabs(r4-24)1e-6:print(f{fmt(combo[0])}{fmt(combo[1])}{fmt(combo[2])}{fmt(combo[3])}:{fmt(a)}{o3}(({fmt(b)}{o1}{fmt(c)}){o2}{fmt(d)}))foundTrue;breakr5calc(calc(a,calc(b,c,o1),o2),d,o3)ifr5isnotNoneandabs(r5-24)1e-6:print(f{fmt(combo[0])}{fmt(combo[1])}{fmt(combo[2])}{fmt(combo[3])}:({fmt(a)}{o2}({fmt(b)}{o1}{fmt(c)})){o3}{fmt(d)})foundTrue;breaksolve()